A rock is thrown vertically upward from the ground with an initial speed 15m/s.
a. how high does it go
b. how much time is required for the rock to reach its maximum height?
c. what is the rock’s height at t=2.00s?
(Posted by Merhawi)
v=0 m/s (at the max height)
(b) From the above case
(c) Use S = ut + 1/2 at2
put t=2s, u = 15m/s, a=-10m/s2
S=30 – 20 = 10 m
(If you use g = 9.8 m/s2 The answers will be slightly different)
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