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  • A numerical problem from motion in 1 Dimension
    AskPhysics Blog Feed A boy plays with a ball on a field surrounded by a fence which has a height of 2.5m . He kicks the ball vertically up from a height of 0.4m with a speed of 14 ms−1. (a) What is the maximum height of the ball above the fence? (b) What is […]

A Numerical Problem – Kinamatics

A particle is thrown vertically upward with a velocity of 19.6 m/s. Find (a) the acceleration of the particle at the highest point. (b) How high the particle will rise? (c) Time taken for rising to highest point.

Eating food during Eclipse

I heard that we ought not eat anything in eclipse hours. Is there any scientific reason for that?

Tejaswini  asked

Answer:

There is no scientific reason behind it. Earlier it was thought that more harmful rays are reaching earth from sun at the time of eclipse. But actually it is less at the time of eclipse as they are blocked by moon coming in its path.

Solar Eclipse

Electricfield, Magnetic Field and Photon

We know that photon has no charge. Then where from it gets electric and magnetic field in light?
Malik Sajad asks
Answer:
Electric and magnetic fields are not produced by the photon; it is massless too.
But, photon is created by time varying electric and magnetic fields, usually produced by accelerated charges.
As you might have already learnt, a charge […]


Problem from relative velocity

A Boat covers certain distance between two spots in a river taking t1 hrs going downstream and t2 hrs going upstream. What time will be taken by boat to cover same distance in still water?
posted by STUTI
Answer:
Incoming search terms:relative velocity linksrelative velocity numericalsLink to this post!


The problem of a rock thrown vertically up

A rock is thrown vertically upward from the ground with an initial speed 15m/s.

a. how high does it go
b. how much time is required for the rock to reach its maximum height?
c. what is the rock’s height at t=2.00s?

(Posted by Merhawi)

Answer:

(a)

u=15m/s

a=-10m/s2

v=0 m/s (at the max height)

S=?

v2-u2=2aS

S=v2-u2/2a

=225/20

=11.25 m

(b) From the above case

using v=u+at

t=v-u/a=1.5s

(c) Use S = ut + 1/2 at2

put t=2s, u = 15m/s, a=-10m/s2

S=30 – 20 = 10 m

(If you use g = 9.8 m/s2 The answers will be slightly different)

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The problem of a rock thrown vertically up

A rock is thrown vertically upward from the ground with an initial speed 15m/s. a. how high does it go b. how much time is required for the rock to reach its maximum height? c. what is the rock’s height at t=2.00s? (Posted by Merhawi) Answer: (a) u=15m/s a=-10m/s2 v=0 m/s (at the max height) […]

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The problem of a rock thrown vertically up

A rock is thrown vertically upward from the ground with an initial speed 15m/s. a. how high does it go b. how much time is required for the rock to reach its maximum height? c. what is the rock’s height at t=2.00s? (Posted by Merhawi) Answer: (a) u=15m/s a=-10m/s2 v=0 m/s (at the max height) […]

No related posts.

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