A Numerical Problem from Projectile Motion
A short is fired from a gun on the top of a hill 90m high with velocity 80m/s at an angle of 30 degree with the horizontal. Find the horizontal distance between the vertical line through the gun and the ponit where the shot strikes the ground? (Shilpa asked this question)
Answer:
Take Sy= -90m
ay= -g=-9.8m/s2
uy= u sin(30) =80 x 0.5 = 40m/s
Substitute in the eqn
s = ut + 0.5 at2
and find t
The horizontal distance Rx = horizontal velocity x time = U cos (30) x time
Substitute for u and t and get the answer
Categories: Answers, Ask Physics, Mechanics, Problem Solving, Problems, Project Tags: answer, hill, horizontal velocity, motion, numerical, numerical problem, ponit, Projectile motion, Substitute, x time
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