Class 12 Physics – (AISSCE)Previous Question Papers with marking scheme

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A simple numerical on momentum

Car mass is 1200 kg moving velocity is 108 km/hr. On applying brakes velocity reduced to 36 km/hr. Find change in momentum? (posted by Aditi) Answer: m=1200 kg u=108 x 5/18=30m/s v=36×5/18=10m/s Change in momentum = m(v-u) = 1200 x (30-10)=1200 ...

A simple numerical on momentum

Car mass is 1200 kg moving velocity is 108 km/hr. On applying brakes velocity reduced to 36 km/hr. Find change in momentum? (posted by Aditi) Answer: m=1200 kg u=108 x 5/18=30m/s v=36×5/18=10m/s Change in momentum = m(v-u) = 1200 x (30-10)=1200 ...

Explain IMPULSE in simple terms

Vimal asked this question. Impulse is the effect of a force and is measured as the change in momentum produced. The same effect, that is the same change in momentum can be produced by a large force acting for a short interval of time, a small force acting for a large interval of time or a moderate [...]

How to describe momentum physically ?

Kiran asks: “How do you describe momentum physically by not in definitions like product of mass and velocity?” Answer: Momentum is defined as “Mass in Motion” or “The quantity of motion“. Momentum is a measure of the “effect” a moving body can produce. It is a measure of the “effort” required to bring a body to [...]

Gain in momentum of a body starting from rest and moving with a uniform acceleration

A mass of 2 g initially  at Rest Travels for 4 sec with and acceleration of 1.5m/s2.The gain of momentum of the body is: This question was posted by Thushar Goyal. Answer: Taking u = 0 m/s, a= 1.5 m/s2 and t = 4 s calculate v v=u+at =6m/s masss, m = 2...