Dimensional Analysis – A solved example

Deduce the dimensional formula for workdone,pressure and density. [posted by boineelo ] Answer: workdone We know that workdone = force x distance Therefore [work done] =  [force] [distance] but force = ma [force]=[m][a] [a]=[velocity]/[t] [velocity]=[displacement]/[t] So, putting all these together [work done]=[m][distance][distance]/[time][time] [work done]=ML2T-2 Similarly, you can work out the dimensional formula for pressure and density as [pressure]=[force]/[area]=ML-1T-2 […]… Read More Dimensional Analysis – A solved example

Physics doubts from Class XI student

How to check the correctness of equation s=u+0.5a(2n-1) using dimensional analysis?(Please describe) In law of conservation of linear momentum derivation,why force acting on body B by A is taken as product of mass and acceleration of "B" and not "A" instead of "B"?   Answer The accuracy is checked as usual, but remember that the… Read More Physics doubts from Class XI student