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    AskPhysics Blog Feed A boy plays with a ball on a field surrounded by a fence which has a height of 2.5m . He kicks the ball vertically up from a height of 0.4m with a speed of 14 ms−1. (a) What is the maximum height of the ball above the fence? (b) What is […]

A particle that doesn’t fit the laws of physics – CERN

Researchers could be very close to finding a FIFTH  fundamental force. Results from the Large Hadron Collider hint at a particle that doesn’t fit the laws of physics. The new particle is believed to be SIX times heavier than the Higgs boson particle.

Further testing is required which is why more ‘collisions’ will commence next month in order to obtain new data. Scientists believe they will have either the ultimate confirmation or refutation of its existence by summer of 2016.

Professor John Ellis, theoretical physicist at Kings College London told the Mail Online in an interview: ‘it would be something completely beyond the Standard Model, and the tip of an iceberg of a large new set of particles if it exists.’

Two of the detectors, ATLAS and CMS, were used to look for new physics and did so by counting ‘particle decays’ that ended up in TWO photons

Researchers believe that this is a good way to push the limits of physics beyond the known because photons are easy to detect and scientists know exactly what to expect in terms of results of background events.

‘It weighs about 750 GeV, corresponding to about six times heavier than the Higgs boson, and almost 800 times heavier than the proton,’ said Professor Ellis.

Questions received via “Ask a Question” section

How to make a radio? Asked Amritansh prasad

 

How many time constant will be elapsed before the power delivered to the battery drops to half of its maximum value? Asked Mrityunjoy

 

Nucleus of an atom consists of neutral neutrons and positively charged protrons… then why do protons not attract neutrons and share charges with them? (+ve charges are supposed to attract neutral & -ve charges,aren’t they? and once they are in contact they share charges!) Asked sree

 

English: Schematic representation of a nucleus...
English: Schematic representation of a nucleus as an ensemble of neutrons and protons (Photo credit: Wikipedia)

 

 

A Numerical Problem – Kinamatics

A particle is thrown vertically upward with a velocity of 19.6 m/s. Find (a) the acceleration of the particle at the highest point. (b) How high the particle will rise? (c) Time taken for rising to highest point.

Horizontal projectile and freely falling body

A rifle at a height H aimed horizontally fires a bullet to the ground. At the same time , a bullet with the same mass in dropped from the same height. Neglecting air resistance, which one hits the ground first?Explain.
ED posted
Answer:
Both will hit the ground simultaneously.
When a body is projected horizontally, its initial vertical velocity […]


The problem of a rock thrown vertically up

A rock is thrown vertically upward from the ground with an initial speed 15m/s.

a. how high does it go
b. how much time is required for the rock to reach its maximum height?
c. what is the rock’s height at t=2.00s?

(Posted by Merhawi)

Answer:

(a)

u=15m/s

a=-10m/s2

v=0 m/s (at the max height)

S=?

v2-u2=2aS

S=v2-u2/2a

=225/20

=11.25 m

(b) From the above case

using v=u+at

t=v-u/a=1.5s

(c) Use S = ut + 1/2 at2

put t=2s, u = 15m/s, a=-10m/s2

S=30 – 20 = 10 m

(If you use g = 9.8 m/s2 The answers will be slightly different)

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The problem of a rock thrown vertically up

A rock is thrown vertically upward from the ground with an initial speed 15m/s. a. how high does it go b. how much time is required for the rock to reach its maximum height? c. what is the rock’s height at t=2.00s? (Posted by Merhawi) Answer: (a) u=15m/s a=-10m/s2 v=0 m/s (at the max height) […]

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The problem of a rock thrown vertically up

A rock is thrown vertically upward from the ground with an initial speed 15m/s. a. how high does it go b. how much time is required for the rock to reach its maximum height? c. what is the rock’s height at t=2.00s? (Posted by Merhawi) Answer: (a) u=15m/s a=-10m/s2 v=0 m/s (at the max height) […]

No related posts.

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