Is the equation for displacement in the n th second dimensionally correct?

S = u + a (n- 1/2)

**Answer:**

Yes

**See the explanation given by Vimal Raj**

If we notice the derivation of this formula

let t1=x and t2=y (for my easiness)

S(y)=uy + 1/2 ay^2———-(1)

S(x)=ux + 1/2 ax^2———–(2)

sub (2) from (1)

S(y)-S(x)=uy + 1/2 ay^2 – ux – 1/2 ax^2

S(y)-S(x)=u(y-x)+a/2(y^2-x^2)

here we know y-x =1 s ,then

Sn = u (1s) + a/2(y+x)(y-x)

Sn =u(1s) + a/2(y+x)(1s)Dimension of Sn must be equal to u(1s)

u=LT^1

THEN Sn=[LT^1][T]=[L]

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