The problem of a rock thrown vertically up
A rock is thrown vertically upward from the ground with an initial speed 15m/s. a. how high does it go b. how much time is required for the rock to reach its maximum height? c. what is the rock’s height at t=2.00s? (Posted by Merhawi) Answer: (a) u=15m/s a=-10m/s2 v=0 m/s [...]
Categories: Ask Physics, dispalcement, KINEMATICS, Mechanics, notion, Nuclear Physics, Project Tags: acceleration, answer, conservation of momentum, distance, gravity, ground, height, height c, initial speed, max, max height, maximum height, Merhawi, numerical problems, Physics, problem, rock, solved, speed, time
The problem of a rock thrown vertically up
A rock is thrown vertically upward from the ground with an initial speed 15m/s. a. how high does it go b. how much time is required for the rock to reach its maximum height? c. what is the rock’s height at t=2.00s? (Posted by Merhawi) Answer: (a) u=1...
Categories: dispalcement, KINEMATICS, Mechanics, notion, Solved Problems Tags: 10m, acceleration, distance, gravity, height, height c, initial speed, max, max height, maximum height, Merhawi, numerical, problem, solved, speed, time
The problem of a rock thrown vertically up
A rock is thrown vertically upward from the ground with an initial speed 15m/s. a. how high does it go b. how much time is required for the rock to reach its maximum height? c. what is the rock’s height at t=2.00s? (Posted by Merhawi) Answer: (a) u=1...
Categories: dispalcement, KINEMATICS, Mechanics, notion, Solved Problems Tags: 10m, acceleration, distance, gravity, height, height c, initial speed, max, max height, maximum height, Merhawi, numerical, problem, solved, speed, time
A simple numerical on momentum
Car mass is 1200 kg moving velocity is 108 km/hr. On applying brakes velocity reduced to 36 km/hr. Find change in momentum? (posted by Aditi) Answer: m=1200 kg u=108 x 5/18=30m/s v=36×5/18=10m/s Change in momentum = m(v-u) = 1200 x (30-10)=1200 ...
Categories: Ask Physics, brakes, Force, Mechanics, Project Tags: 10m, Aditi, answer, brakes, car, change, link, mass, momentum, Physics, post, speed, velocity
A simple numerical on momentum
Car mass is 1200 kg moving velocity is 108 km/hr. On applying brakes velocity reduced to 36 km/hr. Find change in momentum? (posted by Aditi) Answer: m=1200 kg u=108 x 5/18=30m/s v=36×5/18=10m/s Change in momentum = m(v-u) = 1200 x (30-10)=1200 ...
Categories: Ask Physics, brakes, Force, Mechanics, Project Tags: 10m, Aditi, answer, brakes, car, change, mass, momentum, Physics, post, search terms, speed, velocity
Numerical Problem from Friction
“The friction coefficient between a road and the tyre of a vehicle is 4/3.find the maximum incline the road may have so that once hard brakes are applied and the wheel starts skidding,the vehicle going down at a speed of 10m/s is stopped within 5m”...
Categories: Ask Physics, banking, brakes, Force, friction coefficient, friction forces, Mechanics, Project, roads, skidding, tyre, wheel Tags: 10m, brakes, coefficient, friction, friction coefficient, numerical, numerical problem, Physics, post, speed, tyre, vehicle, wheel
