Archimedes Principle states that whenever a body is partially or completely immersed in a liquid it experiences an outward force (called buayant force or upthrust) which is equal to the weight of liquid displaced by the immersed part of the body. Related articles Sure Shot questions in Physics for CBSE Class 9 Summative Assessment (SA1) … Continue reading A Video on Archimedes Principle.

# Category: Mechanics

# Relative Nature of Motion

Now we know that motion is a relative term.So absolute motion has no meaning, right? So aren’t Galileo’s view that earth moves around sun and the church’s old belief that sun moves around earth actually not equally correct or equally wrong? this is a question from hc verma’s concept of physics part 1.(from short answer … Continue reading Relative Nature of Motion

# The problem of a rock thrown vertically up

A rock is thrown vertically upward from the ground with an initial speed 15m/s. a. how high does it go b. how much time is required for the rock to reach its maximum height? c. what is the rock’s height at t=2.00s? (Posted by Merhawi) Answer: (a) u=15m/s a=-10m/s2 v=0 m/s [...]

# The problem of a rock thrown vertically up

A rock is thrown vertically upward from the ground with an initial speed 15m/s. a. how high does it go b. how much time is required for the rock to reach its maximum height? c. what is the rock’s height at t=2.00s? (Posted by Merhawi) Answer: (a) u=1...

# The problem of a rock thrown vertically up

A rock is thrown vertically upward from the ground with an initial speed 15m/s. a. how high does it go b. how much time is required for the rock to reach its maximum height? c. what is the rock’s height at t=2.00s? (Posted by Merhawi) Answer: (a) u=1...

# A simple numerical on momentum

Car mass is 1200 kg moving velocity is 108 km/hr. On applying brakes velocity reduced to 36 km/hr. Find change in momentum? (posted by Aditi) Answer: m=1200 kg u=108 x 5/18=30m/s v=36×5/18=10m/s Change in momentum = m(v-u) = 1200 x (30-10)=1200 ...

# A simple numerical on momentum

Car mass is 1200 kg moving velocity is 108 km/hr. On applying brakes velocity reduced to 36 km/hr. Find change in momentum? (posted by Aditi) Answer: m=1200 kg u=108 x 5/18=30m/s v=36×5/18=10m/s Change in momentum = m(v-u) = 1200 x (30-10)=1200 ...