A simple numerical on momentum
Car mass is 1200 kg moving velocity is 108 km/hr. On applying brakes velocity reduced to 36 km/hr. Find change in momentum? (posted by Aditi) Answer: m=1200 kg u=108 x 5/18=30m/s v=36×5/18=10m/s Change in momentum = m(v-u) = 1200 x (30-10)=1200 ...
Categories: Ask Physics, brakes, Force, Mechanics, Project Tags: 10m, Aditi, answer, brakes, car, change, link, mass, momentum, Physics, post, speed, velocity
A simple numerical on momentum
Car mass is 1200 kg moving velocity is 108 km/hr. On applying brakes velocity reduced to 36 km/hr. Find change in momentum? (posted by Aditi) Answer: m=1200 kg u=108 x 5/18=30m/s v=36×5/18=10m/s Change in momentum = m(v-u) = 1200 x (30-10)=1200 ...
Categories: Ask Physics, brakes, Force, Mechanics, Project Tags: 10m, Aditi, answer, brakes, car, change, mass, momentum, Physics, post, search terms, speed, velocity
Numerical Problem from Friction
“The friction coefficient between a road and the tyre of a vehicle is 4/3.find the maximum incline the road may have so that once hard brakes are applied and the wheel starts skidding,the vehicle going down at a speed of 10m/s is stopped within 5m”...
Categories: Ask Physics, banking, brakes, Force, friction coefficient, friction forces, Mechanics, Project, roads, skidding, tyre, wheel Tags: 10m, brakes, coefficient, friction, friction coefficient, numerical, numerical problem, Physics, post, speed, tyre, vehicle, wheel
Numerical Problem from Motion of Connected systems
Two blocks A and B of mass m1 and m2 respectively are kept in contact on a frictionless table.The experimenter pushes the block A from behind so that the blocks accelerate. If the block A exerts a force F on the block B,what is the force exerted by the experimenter on A. Incoming search terms:numericals on [...]
Categories: Ask Physics, Connected, connected systems, experimenter, Force, m1, m2, Mechanics, Project Tags: connected systems, experimenter, m1, mass, motion, numerical, numerical problem, Physics, problem, search terms
Solution to HC Verma Problem
“Referring to HC Verma Part 2, chapter 29, Electric field and potential, Q 69 I think that Force is inversely proportional to square of the distance between the charged particles, so acceleration is not constant and hence v*v = u*u + 2*a*s is not valid in this case. [...]
Categories: Ask Physics, concept, Electronics, Force, HC VERMA, Physics Links, Project, satyam, v 160 Tags: acceleration, charge, concepts of Physics, Electric, field, Force, h c verma, Incoming, particles, Physics, problem, relative velocity, satyam, search terms, solution, v 160, Verma
Solving problems from kinematics and friction
I just want to know how to easily solve problems related to kinematics and friction. I don’t know why i always face problem in these two topics a lot…… Please help and tell some tricks to solve these both……. THANK U Incoming search terms:class x physics kinematics numericalsfriction physics problemshow to [...]
Categories: Ask Physics, Force, KINEMATICS, lot, Project, solving problems, THANK Tags: class, class X, face, friction, how to, kinematicsLink, Physics, physics kinematics, problem, search terms, solve, solving problems
