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# Category Archives: Exam Help

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## Class X CBSE Results 2014 are ready for Publishing

It is known from reliable sources that the CBSE Result 2014 for Class 10 is ready for publication and the authorities are waiting for a nod from the higher ups. On getting the nod, the results can be published in hours.

If the higher ups give permission, the CBSE Class 10 result may be published even tomorrow. However it is expected that the declaration of results for class 10 will not be delayed more than 22 May 2014, if not published on 20 or 21.

Lakhs of students are eagerly waiting for the results.

## Take care of your health, Exams are near!

‘Sound mind in a sound body’; this is an old saying very relevant to students who are preparing for examination. Remember, you have put in one year of hard work for this ‘D’ day. The marks or grade you score in the examination is not just a jugglery of figures; it is a benchmark of your effort, your performance. I am telling all these not to frighten you, but only to advise you to take some simple steps so that you keep fit to effectively take on the examination and come out successfully.

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Examination is the time when you are glued to your study table for several hours. Therefore, it is the time when you also lack physical exercises. The body requires some rejuvenation. The body cells need enough blood to function properly. So, take at least about one hour of your time for exercises. Go to the nearest park or playground or to your backyard garden. Play with your brother or sister or friend in the neighbor or at least take rigorous walk so that you sweat and in turn make the body relaxed and rejuvenated.

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Keep a tab on your food; totally give up high calorie food and junk food. Instead, switch over to food containing enough protein like fruits, nuts, vegetable salad etc. Drink enough water but reduce on beverages like tea and coffee. Remember, the food you take must supply enough protein and nutrients to your body. If you want you can even consult your physician or dietician who will guide your suitably.

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You must have at least six hours of sound sleep. Some students are in the habit of reading during night. But according to physicians it is always advisable to sleep during night because with that the body gets maximum relaxation. If you have enough sleep you will not carry over the fatigue of the previous day and you feel fully relaxed.

Keep calm
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Last minute preparation always makes you tensed. Therefore if you want to remain calm during the period of examination, the simple remedy is to start studying from the day one of your school or college days. You can also take the help of your teachers who would perhaps even provide with better tips on the method of preparing for various subjects. At the same time, you can also practice yoga and meditation. That would certainly provide you the much needed mental relaxation. Certainly your anxiety level will come down.

Take break
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For example, after every two hours of study, take a short break of about 5 to 10 minutes. Just move out of your study table and walk in your back yard garden. Some students will not agree with this method. But according to educationists, this method of taking short breaks really does wonder. You will be able to retain what all you have studied during the last two hours.

If you follow these simple suggestions certainly you will be able to take your examination ‘head on’ and you will also come out with great success.

## No need to worry over Physics (CBSE)

The evaluation of AISSCE 2012 Physics started and CBSE has prepared a fool proof marking scheme which will give the students the marks they deserve.

However, those who just left the questions unanswered will be at loss; because many of the difficult questions are liberalized but only those who attempted the questions will get the benefit.

Those questions with tougher subdivisions are so evaluated that the easier portions are given more marks than the difficult portions. So, if the students attempted the easier portion and left the difficult portion, the loss is not much.

So, relax!

Your voices are heard, thanks to CBSE for paying heed to us – the teachers and students.

## How was the CBSE Physics Exam 2012?

How was AISSCE Physics Question Paper 2012?

• Was the Board question paper 2012 up to the standard?
• Were there any questions out of syllabus?
• Was any of the questions too tough?
• Were there any unexpected questions?
• How was the numerical problems?
• Did you get sufficient time to answer the questions?

Please post your response soon. Your responses on AISSCE Physics Question Paper 2012 can affect the marking/ evaluation and eventually the marks. Comment honestly.

READ TIMES OF INDIA’s report on AISSCE PHYSICS EXAM 2012 here

aisscephysics2012set2

DOWNLOAD SET 2 OF AISSCE PHYSICS QUESTION PAPER 2012 SET 2 HERE (OUTSIDE DELHI VERSION)

Teachers from different cities have already sent their representation on the problems and anomalies found in the question paper. If your teacher hadn’t done so, Hurry!!!. Request your teachers to have a thorough analysis of the question papers (All sets) and send the difficulties and anomalies in proper format to CBSE. (There is a format available at schools to send anomalies and problems in CBSE question Paper).
CBSE will consider these representations received while finalizing the marking scheme.

Wish you Good Luck ! Dear students.

## Which way is better for giving AIEEE exam? ONLINE or OFFLINE.

Which way is better for giving AIEEE exam? ONLINE or OFFLINE.

I would personally recommend online. But the choice is up to you.

Please follow the following check to decide. Try to identify for yourself the plus points and negative points of writing AIEEE online and OFFLINE.

The most important disadvantage of choosing the OFFLINE version is the rarity of choices. You may have to travel long if you are not nearby the centre.

The decision is yours. But, think well before you decide.

## CBSE PUBLISHED AIEEE ADMISSION NOTICE –2012

CBSE will be conducting the Eleventh All India Engineering/Architecture Entrance Examination (AIEEE), Offline Examination on 29th April, 2012 (Sunday) and Online Examination for B.E./.B.Tech. only from 7th May to 26th May, 2012 for admission to degree level courses in Engineering and Architecture in National Institute of Technologies (NITs), Indian Institute of Information Technologies (IIITs), Centrally funded Institutions, Deemed Universities and Institutions in States/UTs (Other than those covered by Joint Entrance Examination) State Level Entrance Examination.

1. Subject Combination and Mode of Examination
SUBJECTS

Paper 1
Physics, Chemistry & Mathematics

TYPE OF QUESTIONS

Objective type questions with equal weightage to Physics, Chemistry & Mathematics

MODE OF EXAMINATION

BOTH OFFLINE (PAPER/PEN) AND ONLINE (CBT MODE) AS PER SELECTED CITIES

Paper 2
Mathematics – Part I (Objective type questions)
Aptitude Test – Part II (Objective type questions)
& Drawing Test – Part III (questions to test Drawing Aptitude OFFLINE ONLY)

2. Schedule of Examination
AIEEE
will be conducted as per schedule given below:
A. Pen & Paper (Offline examination)
29.04.2012

0930-1230 Hours (3 Hours)

Paper 1

Physics, Chemistry & Mathematics

29.04.2012
1400-1700 Hours (3 Hours)
Paper 2
Mathematics – Part I
Aptitude Test – Part II &
Drawing Test – Part III
B. On line examination for B.E. /B.Tech only (Computer base testing)
7-05-2012 to 26.05.2012
1st shift (9.00 am to 12.00 noon) 2nd shift (2.00 pm to 5.00 pm) 3 Hours

Paper 1
Physics, Chemistry & Mathematics

## Motion in a vertical circle and conservation of energy

A stone  tied to a string of length l is whirled around a vertical circle with the other end of the string at the centre. At a certain instant of time the stone is at the lowest position and has a speed u. What is the magnitude of change in its velocity as it reaches a position where the string is horizontal?

Let’s assume that the potential energy at the lowest position be zero. So, when the string is horizontal, the stone has risen by a vertical height l, the length of the string which is also the radius of the vertical circle.

If v is the magnitude of velocity at the horizontal position, then according to the law of conservation of energy,

KE+PE at the lowest position = KE+PE at the horizontal position

$\frac{1}{2}mu^{2}=\frac{1}{2}mv^{2}+mgl$

From the equation above, v-u can be calculated.

$v=\sqrt{u^{2}-2gl}$

The following links will help you for deeper understanding and you can browse through some solved problems from the topic too.