Exam Help

No need to worry over Physics (CBSE)

The evaluation of AISSCE 2012 Physics started and CBSE has prepared a fool proof marking scheme which will give the students the marks they deserve.

However, those who just left the questions unanswered will be at loss; because many of the difficult questions are liberalized but only those who attempted the questions will get the benefit.

Those questions with tougher subdivisions are so evaluated that the easier portions are given more marks than the difficult portions. So, if the students attempted the easier portion and left the difficult portion, the loss is not much.

So, relax!

Your voices are heard, thanks to CBSE for paying heed to us – the teachers and students.

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• Mark Distribution in Physics for CBSE for 2013 Board Exam (AISSCE) (physicsfans.com)
• How was your AISSCE (CBSE) Chemistry Question Paper 2012? (chemistry.2lv.in)

How was the CBSE Physics Exam 2012?

How was AISSCE Physics Question Paper 2012? Was the Board question paper 2012 up to the standard? Were there any questions out of syllabus? Was any of the questions too tough? Were there any unexpected questions? How was the numerical problems? Did you get sufficient time to answer the questions? Please post your response soon. Your responses on AISSCE Physics Question Paper 2012 can affect the marking/ evaluation and eventually the marks. Comment honestly.

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Which way is better for giving AIEEE exam? ONLINE or OFFLINE.

Which way is better for giving AIEEE exam? ONLINE or OFFLINE.

-Yash asked -

Answer:

I would personally recommend online. But the choice is up to you.

Please follow the following check to decide. Try to identify for yourself the plus points and negative points of writing AIEEE online and OFFLINE.

The most important disadvantage of choosing the OFFLINE version is the rarity of choices. You may have to travel long if you are not nearby the centre.

The decision is yours. But, think well before you decide.

CBSE PUBLISHED AIEEE ADMISSION NOTICE –2012

CBSE will be conducting the Eleventh All India Engineering/Architecture Entrance Examination (AIEEE), Offline Examination on 29th April, 2012 (Sunday) and Online Examination for B.E./.B.Tech. only from 7th May to 26th May, 2012 for admission to degree level courses in Engineering and Architecture in National Institute of Technologies (NITs), Indian Institute of Information Technologies (IIITs), Centrally funded Institutions, Deemed Universities and Institutions in States/UTs (Other than those covered by Joint Entrance Examination) State Level Entrance Examination.

1. Subject Combination and Mode of Examination
SUBJECTS                

Paper 1
Physics, Chemistry & Mathematics

TYPE OF QUESTIONS        

Objective type questions with equal weightage to Physics, Chemistry & Mathematics

MODE OF EXAMINATION

BOTH OFFLINE (PAPER/PEN) AND ONLINE (CBT MODE) AS PER SELECTED CITIES

Paper 2
Mathematics – Part I (Objective type questions)
Aptitude Test – Part II (Objective type questions)
& Drawing Test – Part III (questions to test Drawing Aptitude OFFLINE ONLY)

2. Schedule of Examination
AIEEE will be conducted as per schedule given below:
A. Pen & Paper (Offline examination)
29.04.2012

0930-1230 Hours (3 Hours)

Paper 1

Physics, Chemistry & Mathematics

29.04.2012
1400-1700 Hours (3 Hours)
Paper 2
Mathematics – Part I
Aptitude Test – Part II &
Drawing Test – Part III
B. On line examination for B.E. /B.Tech only (Computer base testing)
7-05-2012 to 26.05.2012
1st shift (9.00 am to 12.00 noon) 2nd shift (2.00 pm to 5.00 pm) 3 Hours

Paper 1
Physics, Chemistry & Mathematics

Motion in a vertical circle and conservation of energy

A stone  tied to a string of length l is whirled around a vertical circle with the other end of the string at the centre. At a certain instant of time the stone is at the lowest position and has a speed u. What is the magnitude of change in its velocity as it reaches a position where the string is horizontal?

Answer:

Let’s assume that the potential energy at the lowest position be zero. So, when the string is horizontal, the stone has risen by a vertical height l, the length of the string which is also the radius of the vertical circle.

If v is the magnitude of velocity at the horizontal position, then according to the law of conservation of energy,

KE+PE at the lowest position = KE+PE at the horizontal position

From the equation above, v-u can be calculated.

The following links will help you for deeper understanding and you can browse through some solved problems from the topic too.

• http://www.tutorvista.com/content/physics/physics-iii/motion-laws/vertical-circle-motion.php
• http://www.goiit.com/posts/show/813363/work-derivation-804230.htm
• http://www.mathsrevision.net/alevel/pages.php?page=85

Questions waiting to be answered at www.askphysics.com

Can you answer these?

A bullet of mass m is fired with a velocity v and strikes a a block of mass M suspended by a string of length L.
the bullet gets embedded in the block. What is the angle the the block makes due to the impact?

Why planets revolve around their own axis?

At time t=0 a ball is projected with a velocity = 60 m/s at 60 degrees form x axis.find the times when the velocity will make angle of 45 degree from x axis?

Suppose that, while lying on a beach near the equator watching the Sun set over a calm ocean, you start a stopwatch just as the top of the Sun disappears.You then stand, elevating your eyes by a height H = 1.70 metres, and stop the watch when the top of the Sun again disappears, If the elapsed time is t=11.1 s, what is the radius r of earth?

A non flow reversible process occurs for which p=3v has power 2+1/v where p is in bar & v is in m has power3. What will be the work done when v changes from 0.5 to 1.5m has power3.

Draw  the ray diagram to show the image formation during looming (mirage in cold regions )?