“A body covers a distance of 20 m in 7th s and 24 m in the 9th s. How much shall it cover in 15s ?” – Raghav posted this question.
Answer: From the eqn for displacement in the nth second,
For the displacement in the 7th sec, we get,
For the displacement in the 9th sec,
24-20 = 2a
or a = 2 m/s2
Substituting for a in (1),
u = 7 m/s
Substituting, u= 7 m/s, a = 2 m/s2 and t = 15 sec in the eqn,
we get S= 7 x 15 + 0.5 x 2x 15 x 15 = 105+225=330m
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